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Check if Two Numbers Are Both Even Using Conditional Operator in C#

In this exercise, we will develop a C# program that determines whether two numbers entered by the user are both even. Instead of using traditional `if` statements, we will utilize the conditional (ternary) operator to assign a boolean variable named `bothEven` the value `true` if both numbers are even, and `false` otherwise. This exercise reinforces the use of conditional operators for concise and efficient decision-making in C#.



Group

C# Basic Data Types Overview

Objective

1. Prompt the user to enter two integer numbers.
2. Use the conditional (ternary) operator to check if both numbers are even.
3. Assign the result to a boolean variable named `bothEven`.
4. Display whether both numbers are even or not based on the value of `bothEven`.
5. Ensure proper input handling to avoid errors when entering non-numeric values.

Write a C# program that uses the conditional operator to give a boolean variable named "bothEven" the value "true" if two numbers entered by the user are even, or "false" if any of them is odd.

Example C# Exercise

 Copy C# Code 
using System;

class Program
{
    static void Main()
    {
        // Prompt user for first number
        Console.Write("Enter the first number: ");
        int num1 = Convert.ToInt32(Console.ReadLine());

        // Prompt user for second number
        Console.Write("Enter the second number: ");
        int num2 = Convert.ToInt32(Console.ReadLine());

        // Use conditional (ternary) operator to check if both numbers are even
        bool bothEven = (num1 % 2 == 0 && num2 % 2 == 0) ? true : false;

        // Display the result
        Console.WriteLine($"Both numbers are even: {bothEven}");
    }
}

 Output

//Example 1:
Enter the first number: 8
Enter the second number: 14
Both numbers are even: True

//Example 2:
Enter the first number: 7
Enter the second number: 10
Both numbers are even: False

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